FSCast #253. Product updates, trainer tips from the pro, and TPGI partnership with AIRA blog.freedomscientific.com/fsc…
FSCast #253. Product updates, trainer tips from the pro, and TPGI partnership with AIRA
On this episode, Elizabeth Whitaker and Oleg Shevkun introduce some of the new features in our December product updates. Then, we hear from Dan Clark aboutFreedom Scientific Blog
![The lemniscate constant $\varpi$ is like a mutant version of the number $\pi$:
\[ \pi = \int_{-1}^1 \frac{dx}{\sqrt{1 - x^2}} \approx 3.14159 \]
\[ \varpi = \int_{-1}^1 \frac{dx}{\sqrt{1 - x^4}} \approx 2.622057 \]
It obeys a lot of similar formulas. For example:
\[ \frac2\pi = \sqrt\frac12 \cdot \sqrt{\frac12 + \frac12\sqrt\frac12} \cdot \sqrt{\frac12 + \frac12\sqrt{\frac12 + \frac12\sqrt\frac12}} \cdots \]
\[
\frac2\varpi = \sqrt\frac12 \cdot \sqrt{\frac12 + \frac12 \bigg/ \!\sqrt\frac12} \cdot \sqrt{\frac12 + \frac12 \Bigg/ \!\sqrt{\frac12 + \frac12 \bigg/ \!\sqrt\frac12}} \cdots
\]](https://fedi.ml/photo/preview/640/620497 "The lemniscate constant $\varpi$ is like a mutant version of the number $\pi$:
\[ \pi = \int_{-1}^1 \frac{dx}{\sqrt{1 - x^2}} \approx 3.14159 \]
\[ \varpi = \int_{-1}^1 \frac{dx}{\sqrt{1 - x^4}} \approx 2.622057 \]
It obeys a lot of similar formulas. For example:
\[ \frac2\pi = \sqrt\frac12 \cdot \sqrt{\frac12 + \frac12\sqrt\frac12} \cdot \sqrt{\frac12 + \frac12\sqrt{\frac12 + \frac12\sqrt\frac12}} \cdots \]
\[
\frac2\varpi = \sqrt\frac12 \cdot \sqrt{\frac12 + \frac12 \bigg/ \!\sqrt\frac12} \cdot \sqrt{\frac12 + \frac12 \Bigg/ \!\sqrt{\frac12 + \frac12 \bigg/ \!\sqrt\frac12}} \cdots
\]")
Jan Johannesson
in reply to daniel:// stenberg:// • • •Jonathan Yu
in reply to daniel:// stenberg:// • • •Derick Rethans
in reply to daniel:// stenberg:// • • •daniel:// stenberg://
in reply to Derick Rethans • • •skry
in reply to daniel:// stenberg:// • • •xkcd.com/2347/
Sorry you were mis-nationed. Thanks for your frivolous work on inconsequential hobby tools, lol.
Dependency
xkcdpatcanfield
in reply to daniel:// stenberg:// • • •Arnaud Launay
in reply to daniel:// stenberg:// • • •